8b^2-10=525

Solution for 8b^2-10=525 equation:

8b^2-10=525

We move all terms to the left:

8b^2-10-(525)=0

We add all the numbers together, and all the variables

8b^2-535=0

a = 8; b = 0; c = -535;
Δ = b2-4ac
Δ = 02-4·8·(-535)
Δ = 17120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17120}=\sqrt{16*1070}=\sqrt{16}*\sqrt{1070}=4\sqrt{1070}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1070}}{2*8}=\frac{0-4\sqrt{1070}}{16}
=-\frac{4\sqrt{1070}}{16}
=-\frac{\sqrt{1070}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1070}}{2*8}=\frac{0+4\sqrt{1070}}{16}
=\frac{4\sqrt{1070}}{16}
=\frac{\sqrt{1070}}{4}
$